0=x^2+3x-56

Solution for 0=x^2+3x-56 equation:

0=x^2+3x-56

We move all terms to the left:

0-(x^2+3x-56)=0

We add all the numbers together, and all the variables

-(x^2+3x-56)=0

We get rid of parentheses

-x^2-3x+56=0

We add all the numbers together, and all the variables

-1x^2-3x+56=0

a = -1; b = -3; c = +56;
Δ = b2-4ac
Δ = -32-4·(-1)·56
Δ = 233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{233}}{2*-1}=\frac{3-\sqrt{233}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{233}}{2*-1}=\frac{3+\sqrt{233}}{-2}
$